2x+(3y+1)=2x+(1+3y)

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Solution for 2x+(3y+1)=2x+(1+3y) equation:


Simplifying
2x + (3y + 1) = 2x + (1 + 3y)

Reorder the terms:
2x + (1 + 3y) = 2x + (1 + 3y)

Remove parenthesis around (1 + 3y)
2x + 1 + 3y = 2x + (1 + 3y)

Reorder the terms:
1 + 2x + 3y = 2x + (1 + 3y)

Remove parenthesis around (1 + 3y)
1 + 2x + 3y = 2x + 1 + 3y

Reorder the terms:
1 + 2x + 3y = 1 + 2x + 3y

Add '-1' to each side of the equation.
1 + 2x + -1 + 3y = 1 + 2x + -1 + 3y

Reorder the terms:
1 + -1 + 2x + 3y = 1 + 2x + -1 + 3y

Combine like terms: 1 + -1 = 0
0 + 2x + 3y = 1 + 2x + -1 + 3y
2x + 3y = 1 + 2x + -1 + 3y

Reorder the terms:
2x + 3y = 1 + -1 + 2x + 3y

Combine like terms: 1 + -1 = 0
2x + 3y = 0 + 2x + 3y
2x + 3y = 2x + 3y

Add '-2x' to each side of the equation.
2x + -2x + 3y = 2x + -2x + 3y

Combine like terms: 2x + -2x = 0
0 + 3y = 2x + -2x + 3y
3y = 2x + -2x + 3y

Combine like terms: 2x + -2x = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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