2x+(41-x)(4)=106

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Solution for 2x+(41-x)(4)=106 equation: 



2x+(41-x)(4)=106

We move all terms to the left:

2x+(41-x)(4)-(106)=0

We add all the numbers together, and all the variables

2x+(-1x+41)4-106=0

We multiply parentheses

2x-4x+164-106=0

We add all the numbers together, and all the variables

-2x+58=0

We move all terms containing x to the left, all other terms to the right

-2x=-58

x=-58/-2

x=+29

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