2x+(5/2)=(3/x)

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Solution for 2x+(5/2)=(3/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+5/2 = 3/x // - 3/x

2*x-(3/x)+5/2 = 0

2*x-3*x^-1+5/2 = 0

2*x^1-3*x^-1+5/2*x^0 = 0

(2*x^2+5/2*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+5/2*x^1-3*x^0) = 0

x^1

2*x^2+(5/2)*x-3 = 0

2*x^2+(5/2)*x-3 = 0

DELTA = (5/2)^2-(-3*2*4)

DELTA = 121/4

DELTA > 0

x = ((121/4)^(1/2)-(5/2))/(2*2) or x = (-(5/2)-(121/4)^(1/2))/(2*2)

x = 3/4 or x = -2

x in { -2, 3/4} 

x in { -2, 3/4 }

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