2x+(5/x)=23/3

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Solution for 2x+(5/x)=23/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+5/x = 23/3 // - 23/3

2*x+5/x-(23/3) = 0

2*x+5/x-23/3 = 0

2*x^1+5*x^-1-23/3*x^0 = 0

(2*x^2-23/3*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-23/3*x^1+5*x^0) = 0

x^1

2*x^2+(-23/3)*x+5 = 0

2*x^2+(-23/3)*x+5 = 0

DELTA = (-23/3)^2-(2*4*5)

DELTA = 169/9

DELTA > 0

x = ((169/9)^(1/2)-(-23/3))/(2*2) or x = (-(-23/3)-(169/9)^(1/2))/(2*2)

x = 3 or x = 5/6

x in { 5/6, 3} 

x in { 5/6, 3 }

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