2x+(7/3x)=23

Solution for 2x+(7/3x)=23 equation:

2x+(7/3x)=23

We move all terms to the left:

2x+(7/3x)-(23)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+7/3x)-23=0

We get rid of parentheses

2x+7/3x-23=0

We multiply all the terms by the denominator


2x*3x-23*3x+7=0

Wy multiply elements

6x^2-69x+7=0

a = 6; b = -69; c = +7;
Δ = b2-4ac
Δ = -692-4·6·7
Δ = 4593
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-\sqrt{4593}}{2*6}=\frac{69-\sqrt{4593}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+\sqrt{4593}}{2*6}=\frac{69+\sqrt{4593}}{12}
$