2x+(72/x)=26

Solution for 2x+(72/x)=26 equation:

2x+(72/x)=26

We move all terms to the left:

2x+(72/x)-(26)=0


Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x+(+72/x)-26=0

We get rid of parentheses

2x+72/x-26=0

We multiply all the terms by the denominator


2x*x-26*x+72=0

We add all the numbers together, and all the variables

-26x+2x*x+72=0

Wy multiply elements

2x^2-26x+72=0

a = 2; b = -26; c = +72;
Δ = b2-4ac
Δ = -262-4·2·72
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*2}=\frac{16}{4}
=4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*2}=\frac{36}{4}
=9
$