2x+(8-3x)=(x-4)

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Solution for 2x+(8-3x)=(x-4) equation: 



2x+(8-3x)=(x-4)

We move all terms to the left:

2x+(8-3x)-((x-4))=0

We add all the numbers together, and all the variables

2x+(-3x+8)-((x-4))=0

We get rid of parentheses

2x-3x-((x-4))+8=0



We calculate terms in parentheses: -((x-4)), so:

(x-4)

We get rid of parentheses

x-4

Back to the equation:

-(x-4)



We add all the numbers together, and all the variables

-1x-(x-4)+8=0

We get rid of parentheses

-1x-x+4+8=0

We add all the numbers together, and all the variables

-2x+12=0

We move all terms containing x to the left, all other terms to the right

-2x=-12

x=-12/-2

x=+6

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