2x+(x+12)+(3x-9)=117

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Solution for 2x+(x+12)+(3x-9)=117 equation:


Simplifying
2x + (x + 12) + (3x + -9) = 117

Reorder the terms:
2x + (12 + x) + (3x + -9) = 117

Remove parenthesis around (12 + x)
2x + 12 + x + (3x + -9) = 117

Reorder the terms:
2x + 12 + x + (-9 + 3x) = 117

Remove parenthesis around (-9 + 3x)
2x + 12 + x + -9 + 3x = 117

Reorder the terms:
12 + -9 + 2x + x + 3x = 117

Combine like terms: 12 + -9 = 3
3 + 2x + x + 3x = 117

Combine like terms: 2x + x = 3x
3 + 3x + 3x = 117

Combine like terms: 3x + 3x = 6x
3 + 6x = 117

Solving
3 + 6x = 117

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 6x = 117 + -3

Combine like terms: 3 + -3 = 0
0 + 6x = 117 + -3
6x = 117 + -3

Combine like terms: 117 + -3 = 114
6x = 114

Divide each side by '6'.
x = 19

Simplifying
x = 19

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