2x+(x-4)+(25-2x+(x-4))=25

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Solution for 2x+(x-4)+(25-2x+(x-4))=25 equation: 



2x+(x-4)+(25-2x+(x-4))=25

We move all terms to the left:

2x+(x-4)+(25-2x+(x-4))-(25)=0

We get rid of parentheses

2x+x+(25-2x+(x-4))-4-25=0



We calculate terms in parentheses: +(25-2x+(x-4)), so:

25-2x+(x-4)

determiningTheFunctionDomain
-2x+(x-4)+25

We get rid of parentheses

-2x+x-4+25

We add all the numbers together, and all the variables

-1x+21

Back to the equation:

+(-1x+21)



We add all the numbers together, and all the variables

3x+(-1x+21)-29=0

We get rid of parentheses

3x-1x+21-29=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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