2x+(y+z)=(2x+y)+z

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Solution for 2x+(y+z)=(2x+y)+z equation:


Simplifying
2x + (y + z) = (2x + y) + z

Remove parenthesis around (y + z)
2x + y + z = (2x + y) + z

Remove parenthesis around (2x + y)
2x + y + z = 2x + y + z

Add '-2x' to each side of the equation.
2x + y + -2x + z = 2x + y + -2x + z

Reorder the terms:
2x + -2x + y + z = 2x + y + -2x + z

Combine like terms: 2x + -2x = 0
0 + y + z = 2x + y + -2x + z
y + z = 2x + y + -2x + z

Reorder the terms:
y + z = 2x + -2x + y + z

Combine like terms: 2x + -2x = 0
y + z = 0 + y + z
y + z = y + z

Add '-1y' to each side of the equation.
y + -1y + z = y + -1y + z

Combine like terms: y + -1y = 0
0 + z = y + -1y + z
z = y + -1y + z

Combine like terms: y + -1y = 0
z = 0 + z
z = z

Add '-1z' to each side of the equation.
z + -1z = z + -1z

Combine like terms: z + -1z = 0
0 = z + -1z

Combine like terms: z + -1z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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