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2x+-1x2=15

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Solution for 2x+-1x2=15 equation:



2x+-1x^2=15
We move all terms to the left:
2x+-1x^2-(15)=0
determiningTheFunctionDomain -1x^2+2x-15+=0
We add all the numbers together, and all the variables
-1x^2+2x=0
a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}

\sqrt{\Delta}=\sqrt{4}=2
x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2} =+2
x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2} =0

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