2x+-2=3(x+-1)+-5(6+-2x)

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Solution for 2x+-2=3(x+-1)+-5(6+-2x) equation: 



2x+-2=3(x+-1)+-5(6+-2x)

We move all terms to the left:

2x+-2-(3(x+-1)+-5(6+-2x))=0

We add all the numbers together, and all the variables

2x-(3(x-1)+-5(-2x))-2+=0

We add all the numbers together, and all the variables

2x-(3(x-1)+-5(-2x))=0

We use the square of the difference formula

2x-(3(x-1)-5(-2x))=0



We calculate terms in parentheses: -(3(x-1)-5(-2x)), so:

3(x-1)-5(-2x)

We multiply parentheses

3x+10x-3

We add all the numbers together, and all the variables

13x-3

Back to the equation:

-(13x-3)



We get rid of parentheses

2x-13x+3=0

We add all the numbers together, and all the variables

-11x+3=0

We move all terms containing x to the left, all other terms to the right

-11x=-3

x=-3/-11

x=3/11

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