2x+1+4x+19=8x-10

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Solution for 2x+1+4x+19=8x-10 equation: 



2x+1+4x+19=8x-10

We move all terms to the left:

2x+1+4x+19-(8x-10)=0

We add all the numbers together, and all the variables

6x-(8x-10)+20=0

We get rid of parentheses

6x-8x+10+20=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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