2x+1+5(x-3)=3(X+1)=Y

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Solution for 2x+1+5(x-3)=3(X+1)=Y equation: 



2x+1+5(x-3)=3(x+1)=

We move all terms to the left:

2x+1+5(x-3)-(3(x+1))=0

We multiply parentheses

2x+5x-(3(x+1))-15+1=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

7x-(3x+3)-14=0

We get rid of parentheses

7x-3x-3-14=0

We add all the numbers together, and all the variables

4x-17=0

We move all terms containing x to the left, all other terms to the right

4x=17

x=17/4

x=4+1/4

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