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2x+1+5x*2x-1=36
We move all terms to the left:
2x+1+5x*2x-1-(36)=0
We add all the numbers together, and all the variables
2x+5x*2x-36=0
Wy multiply elements
10x^2+2x-36=0
a = 10; b = 2; c = -36;
Δ = b2-4ac
Δ = 22-4·10·(-36)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*10}=\frac{-40}{20} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*10}=\frac{36}{20} =1+4/5 $
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