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2x+1+x=3(x-2)+1
We move all terms to the left:
2x+1+x-(3(x-2)+1)=0
We add all the numbers together, and all the variables
3x-(3(x-2)+1)+1=0
We calculate terms in parentheses: -(3(x-2)+1), so:We get rid of parentheses
3(x-2)+1
We multiply parentheses
3x-6+1
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
3x-3x+5+1=0
We add all the numbers together, and all the variables
6!=0
There is no solution for this equation
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