2x+1-(2+x)-7=3(x+1)

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Solution for 2x+1-(2+x)-7=3(x+1) equation: 



2x+1-(2+x)-7=3(x+1)

We move all terms to the left:

2x+1-(2+x)-7-(3(x+1))=0

We add all the numbers together, and all the variables

2x-(x+2)-(3(x+1))+1-7=0

We add all the numbers together, and all the variables

2x-(x+2)-(3(x+1))-6=0

We get rid of parentheses

2x-x-(3(x+1))-2-6=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We add all the numbers together, and all the variables

x-(3x+3)-8=0

We get rid of parentheses

x-3x-3-8=0

We add all the numbers together, and all the variables

-2x-11=0

We move all terms containing x to the left, all other terms to the right

-2x=11

x=11/-2

x=-5+1/2

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