2x+1-(2x-4)=4-2*(3-2x)

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Solution for 2x+1-(2x-4)=4-2*(3-2x) equation: 



2x+1-(2x-4)=4-2(3-2x)

We move all terms to the left:

2x+1-(2x-4)-(4-2(3-2x))=0

We add all the numbers together, and all the variables

2x-(2x-4)-(4-2(-2x+3))+1=0

We get rid of parentheses

2x-2x-(4-2(-2x+3))+4+1=0



We calculate terms in parentheses: -(4-2(-2x+3)), so:

4-2(-2x+3)

determiningTheFunctionDomain
-2(-2x+3)+4

We multiply parentheses

4x-6+4

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

-(4x-2)+5=0

We get rid of parentheses

-4x+2+5=0

We add all the numbers together, and all the variables

-4x+7=0

We move all terms containing x to the left, all other terms to the right

-4x=-7

x=-7/-4

x=1+3/4

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