2x+1-3(2+x)=2-3(2+x)+x

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Solution for 2x+1-3(2+x)=2-3(2+x)+x equation: 



2x+1-3(2+x)=2-3(2+x)+x

We move all terms to the left:

2x+1-3(2+x)-(2-3(2+x)+x)=0

We add all the numbers together, and all the variables

2x-3(x+2)-(2-3(x+2)+x)+1=0

We multiply parentheses

2x-3x-(2-3(x+2)+x)-6+1=0



We calculate terms in parentheses: -(2-3(x+2)+x), so:

2-3(x+2)+x

determiningTheFunctionDomain
-3(x+2)+x+2

We add all the numbers together, and all the variables

x-3(x+2)+2

We multiply parentheses

x-3x-6+2

We add all the numbers together, and all the variables

-2x-4

Back to the equation:

-(-2x-4)



We add all the numbers together, and all the variables

-1x-(-2x-4)-5=0

We get rid of parentheses

-1x+2x+4-5=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1

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