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2x+1-x=8-(3x+3)
We move all terms to the left:
2x+1-x-(8-(3x+3))=0
We add all the numbers together, and all the variables
x-(8-(3x+3))+1=0
We calculate terms in parentheses: -(8-(3x+3)), so:We get rid of parentheses
8-(3x+3)
determiningTheFunctionDomain -(3x+3)+8
We get rid of parentheses
-3x-3+8
We add all the numbers together, and all the variables
-3x+5
Back to the equation:
-(-3x+5)
x+3x-5+1=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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