2x+1/2x+3=105

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Solution for 2x+1/2x+3=105 equation:



2x+1/2x+3=105
We move all terms to the left:
2x+1/2x+3-(105)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
2x+1/2x-102=0
We multiply all the terms by the denominator
2x*2x-102*2x+1=0
Wy multiply elements
4x^2-204x+1=0
a = 4; b = -204; c = +1;
Δ = b2-4ac
Δ = -2042-4·4·1
Δ = 41600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{41600}=\sqrt{1600*26}=\sqrt{1600}*\sqrt{26}=40\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-204)-40\sqrt{26}}{2*4}=\frac{204-40\sqrt{26}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-204)+40\sqrt{26}}{2*4}=\frac{204+40\sqrt{26}}{8} $

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