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2x+1/2x-1=31
We move all terms to the left:
2x+1/2x-1-(31)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2x+1/2x-32=0
We multiply all the terms by the denominator
2x*2x-32*2x+1=0
Wy multiply elements
4x^2-64x+1=0
a = 4; b = -64; c = +1;
Δ = b2-4ac
Δ = -642-4·4·1
Δ = 4080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4080}=\sqrt{16*255}=\sqrt{16}*\sqrt{255}=4\sqrt{255}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-4\sqrt{255}}{2*4}=\frac{64-4\sqrt{255}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+4\sqrt{255}}{2*4}=\frac{64+4\sqrt{255}}{8} $
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