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2x+1/2x=1500
We move all terms to the left:
2x+1/2x-(1500)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
2x*2x-1500*2x+1=0
Wy multiply elements
4x^2-3000x+1=0
a = 4; b = -3000; c = +1;
Δ = b2-4ac
Δ = -30002-4·4·1
Δ = 8999984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8999984}=\sqrt{16*562499}=\sqrt{16}*\sqrt{562499}=4\sqrt{562499}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3000)-4\sqrt{562499}}{2*4}=\frac{3000-4\sqrt{562499}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3000)+4\sqrt{562499}}{2*4}=\frac{3000+4\sqrt{562499}}{8} $
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