2x+1/3*x=21

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Solution for 2x+1/3*x=21 equation:



2x+1/3x=21
We move all terms to the left:
2x+1/3x-(21)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We multiply all the terms by the denominator
2x*3x-21*3x+1=0
Wy multiply elements
6x^2-63x+1=0
a = 6; b = -63; c = +1;
Δ = b2-4ac
Δ = -632-4·6·1
Δ = 3945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-\sqrt{3945}}{2*6}=\frac{63-\sqrt{3945}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+\sqrt{3945}}{2*6}=\frac{63+\sqrt{3945}}{12} $

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