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2x+1/3-(x-4/6)=x-(3x-4/5)
We move all terms to the left:
2x+1/3-(x-4/6)-(x-(3x-4/5))=0
We add all the numbers together, and all the variables
2x-(+x-4/6)-(x-(+3x-4/5))+1/3=0
We get rid of parentheses
2x-x-(x-(+3x-4/5))+4/6+1/3=0
We calculate fractions
2x-x+(-(x-(+3x-4*6*3)/()+()/()+()/()=0
We calculate terms in parentheses: +(-(x-(+3x-4*6*3)/()+()/()+()/(), so:
-(x-(+3x-4*6*3)/()+()/()+()/(
We can not solve this equation
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