2x+1/3=(x-1)/2

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Solution for 2x+1/3=(x-1)/2 equation: 



2x+1/3=(x-1)/2

We move all terms to the left:

2x+1/3-((x-1)/2)=0

We calculate fractions


2x+(-((x-1)*3)/()+()/()=0



We calculate terms in parentheses: +(-((x-1)*3)/()+()/(), so:

-((x-1)*3)/()+()/(

We add all the numbers together, and all the variables

-((x-1)*3)/()+1

We multiply all the terms by the denominator


-((x-1)*3)+1*()



We calculate terms in parentheses: -((x-1)*3), so:

(x-1)*3

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

-(3x-3)

We get rid of parentheses

-3x+3

Back to the equation:

+(-3x+3)



We get rid of parentheses

2x-3x+3=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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