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2x+1/4=1/3(x-4)
We move all terms to the left:
2x+1/4-(1/3(x-4))=0
Domain of the equation: 3(x-4))!=0We calculate fractions
x∈R
2x+()/12x+(3xx/12x=0
We multiply all the terms by the denominator
2x*12x+(3xx+()=0
We calculate terms in parentheses: +(3xx+(), so:Wy multiply elements
3xx+(
We add all the numbers together, and all the variables
3xx
Back to the equation:
+(3xx)
24x^2+3xx=0
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