2x+1/4x=135

Solution for 2x+1/4x=135 equation:

2x+1/4x=135

We move all terms to the left:

2x+1/4x-(135)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We multiply all the terms by the denominator


2x*4x-135*4x+1=0

Wy multiply elements

8x^2-540x+1=0

a = 8; b = -540; c = +1;
Δ = b2-4ac
Δ = -5402-4·8·1
Δ = 291568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{291568}=\sqrt{16*18223}=\sqrt{16}*\sqrt{18223}=4\sqrt{18223}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-540)-4\sqrt{18223}}{2*8}=\frac{540-4\sqrt{18223}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-540)+4\sqrt{18223}}{2*8}=\frac{540+4\sqrt{18223}}{16}
$