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2x+1/4x=360
We move all terms to the left:
2x+1/4x-(360)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
2x*4x-360*4x+1=0
Wy multiply elements
8x^2-1440x+1=0
a = 8; b = -1440; c = +1;
Δ = b2-4ac
Δ = -14402-4·8·1
Δ = 2073568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2073568}=\sqrt{16*129598}=\sqrt{16}*\sqrt{129598}=4\sqrt{129598}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1440)-4\sqrt{129598}}{2*8}=\frac{1440-4\sqrt{129598}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1440)+4\sqrt{129598}}{2*8}=\frac{1440+4\sqrt{129598}}{16} $
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