2x+1/5-3x-4/2=2

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Solution for 2x+1/5-3x-4/2=2 equation: 



2x+1/5-3x-4/2=2

We move all terms to the left:

2x+1/5-3x-4/2-(2)=0

determiningTheFunctionDomain
2x-3x-2+1/5-4/2=0

We add all the numbers together, and all the variables

-1x-4+1/5=0

We multiply all the terms by the denominator


-1x*5+1-4*5=0

We add all the numbers together, and all the variables

-1x*5-19=0

Wy multiply elements

-5x-19=0

We move all terms containing x to the left, all other terms to the right

-5x=19

x=19/-5

x=-3+4/5

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