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2x+1/6x-5=0
Domain of the equation: 6x!=0We multiply all the terms by the denominator
x!=0/6
x!=0
x∈R
2x*6x-5*6x+1=0
Wy multiply elements
12x^2-30x+1=0
a = 12; b = -30; c = +1;
Δ = b2-4ac
Δ = -302-4·12·1
Δ = 852
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{852}=\sqrt{4*213}=\sqrt{4}*\sqrt{213}=2\sqrt{213}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{213}}{2*12}=\frac{30-2\sqrt{213}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{213}}{2*12}=\frac{30+2\sqrt{213}}{24} $
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