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2x+1/6x=-3
We move all terms to the left:
2x+1/6x-(-3)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
2x+1/6x+3=0
We multiply all the terms by the denominator
2x*6x+3*6x+1=0
Wy multiply elements
12x^2+18x+1=0
a = 12; b = 18; c = +1;
Δ = b2-4ac
Δ = 182-4·12·1
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{69}}{2*12}=\frac{-18-2\sqrt{69}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{69}}{2*12}=\frac{-18+2\sqrt{69}}{24} $
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