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2x+1/6x=3x-15
We move all terms to the left:
2x+1/6x-(3x-15)=0
Domain of the equation: 6x!=0We get rid of parentheses
x!=0/6
x!=0
x∈R
2x+1/6x-3x+15=0
We multiply all the terms by the denominator
2x*6x-3x*6x+15*6x+1=0
Wy multiply elements
12x^2-18x^2+90x+1=0
We add all the numbers together, and all the variables
-6x^2+90x+1=0
a = -6; b = 90; c = +1;
Δ = b2-4ac
Δ = 902-4·(-6)·1
Δ = 8124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8124}=\sqrt{4*2031}=\sqrt{4}*\sqrt{2031}=2\sqrt{2031}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-2\sqrt{2031}}{2*-6}=\frac{-90-2\sqrt{2031}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+2\sqrt{2031}}{2*-6}=\frac{-90+2\sqrt{2031}}{-12} $
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