2x+10(3x-5)=80

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Solution for 2x+10(3x-5)=80 equation: 



2x+10(3x-5)=80

We move all terms to the left:

2x+10(3x-5)-(80)=0

We multiply parentheses

2x+30x-50-80=0

We add all the numbers together, and all the variables

32x-130=0

We move all terms containing x to the left, all other terms to the right

32x=130

x=130/32

x=4+1/16

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