2x+10-2(6x-3)=5-12x+2(x-1)

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Solution for 2x+10-2(6x-3)=5-12x+2(x-1) equation: 



2x+10-2(6x-3)=5-12x+2(x-1)

We move all terms to the left:

2x+10-2(6x-3)-(5-12x+2(x-1))=0

We multiply parentheses

2x-12x-(5-12x+2(x-1))+6+10=0



We calculate terms in parentheses: -(5-12x+2(x-1)), so:

5-12x+2(x-1)

determiningTheFunctionDomain
-12x+2(x-1)+5

We multiply parentheses

-12x+2x-2+5

We add all the numbers together, and all the variables

-10x+3

Back to the equation:

-(-10x+3)



We add all the numbers together, and all the variables

-10x-(-10x+3)+16=0

We get rid of parentheses

-10x+10x-3+16=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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