2x+10=6x(2)

Solution for 2x+10=6x(2) equation:

2x+10=6x(2)

We move all terms to the left:

2x+10-(6x(2))=0

determiningTheFunctionDomain
2x-6x2+10=0

We add all the numbers together, and all the variables

-6x^2+2x+10=0

a = -6; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·(-6)·10
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{61}}{2*-6}=\frac{-2-2\sqrt{61}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{61}}{2*-6}=\frac{-2+2\sqrt{61}}{-12}
$