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2x+12+12=2(x-2)+16+16
We move all terms to the left:
2x+12+12-(2(x-2)+16+16)=0
We add all the numbers together, and all the variables
2x-(2(x-2)+16+16)+24=0
We calculate terms in parentheses: -(2(x-2)+16+16), so:We get rid of parentheses
2(x-2)+16+16
We add all the numbers together, and all the variables
2(x-2)+32
We multiply parentheses
2x-4+32
We add all the numbers together, and all the variables
2x+28
Back to the equation:
-(2x+28)
2x-2x-28+24=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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