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2x+12-8+7x=5(x-3)=1
We move all terms to the left:
2x+12-8+7x-(5(x-3))=0
We add all the numbers together, and all the variables
9x-(5(x-3))+4=0
We calculate terms in parentheses: -(5(x-3)), so:We get rid of parentheses
5(x-3)
We multiply parentheses
5x-15
Back to the equation:
-(5x-15)
9x-5x+15+4=0
We add all the numbers together, and all the variables
4x+19=0
We move all terms containing x to the left, all other terms to the right
4x=-19
x=-19/4
x=-4+3/4
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