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2x+12=11(x+3/8)
We move all terms to the left:
2x+12-(11(x+3/8))=0
We add all the numbers together, and all the variables
2x-(11(+x+3/8))+12=0
We multiply all the terms by the denominator
2x*8))-(11(+x+3+12*8))=0
We add all the numbers together, and all the variables
2x*8))-(11(x+99))=0
We add all the numbers together, and all the variables
2x*8))-(11(x=0
Wy multiply elements
16x^2=0
a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{32}=0$
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