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2x+12=3x+(-2x+5)
We move all terms to the left:
2x+12-(3x+(-2x+5))=0
We calculate terms in parentheses: -(3x+(-2x+5)), so:We get rid of parentheses
3x+(-2x+5)
We get rid of parentheses
3x-2x+5
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
2x-x-5+12=0
We add all the numbers together, and all the variables
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7
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