2x+12=3x+6-x-(-6)

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Solution for 2x+12=3x+6-x-(-6) equation: 



2x+12=3x+6-x-(-6)

We move all terms to the left:

2x+12-(3x+6-x-(-6))=0



We calculate terms in parentheses: -(3x+6-x-(-6)), so:

3x+6-x-(-6)

determiningTheFunctionDomain
3x-x+6-(-6)

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

2x-2x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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