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2x+12x+28=6x+40+5x
We move all terms to the left:
2x+12x+28-(6x+40+5x)=0
We add all the numbers together, and all the variables
2x+12x-(11x+40)+28=0
We add all the numbers together, and all the variables
14x-(11x+40)+28=0
We get rid of parentheses
14x-11x-40+28=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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