2x+14+5x(x-7)=0

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Solution for 2x+14+5x(x-7)=0 equation:



2x+14+5x(x-7)=0
We multiply parentheses
5x^2+2x-35x+14=0
We add all the numbers together, and all the variables
5x^2-33x+14=0
a = 5; b = -33; c = +14;
Δ = b2-4ac
Δ = -332-4·5·14
Δ = 809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{809}}{2*5}=\frac{33-\sqrt{809}}{10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{809}}{2*5}=\frac{33+\sqrt{809}}{10} $

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