2x+1=(x+4)x5/8

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Solution for 2x+1=(x+4)x5/8 equation: 



2x+1=(x+4)x5/8

We move all terms to the left:

2x+1-((x+4)x5/8)=0

We multiply all the terms by the denominator


2x*8)-((x+4)x5+1*8)=0

We add all the numbers together, and all the variables

2x*8)-((x+4)x5=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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