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2x+1=1/3(3-9x)
We move all terms to the left:
2x+1-(1/3(3-9x))=0
Domain of the equation: 3(3-9x))!=0We add all the numbers together, and all the variables
x∈R
2x-(1/3(-9x+3))+1=0
We multiply all the terms by the denominator
2x*3(-9x+3))-(1+1*3(-9x+3))=0
Wy multiply elements
6x^2(-+3x(-=0
We use the square of the difference formula
6x^2(-3x(-=0
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