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2x+1=3-(2-2x)
We move all terms to the left:
2x+1-(3-(2-2x))=0
We add all the numbers together, and all the variables
2x-(3-(-2x+2))+1=0
We calculate terms in parentheses: -(3-(-2x+2)), so:We get rid of parentheses
3-(-2x+2)
determiningTheFunctionDomain -(-2x+2)+3
We get rid of parentheses
2x-2+3
We add all the numbers together, and all the variables
2x+1
Back to the equation:
-(2x+1)
2x-2x-1+1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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