2x+1=9/(x+2)

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Solution for 2x+1=9/(x+2) equation:


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

2*x+1 = 9/(x+2) // - 9/(x+2)

2*x-(9/(x+2))+1 = 0

2*x-9*(x+2)^-1+1 = 0

2*x-9/(x+2)+1 = 0

(2*x*(x+2))/(x+2)-9/(x+2)+(1*(x+2))/(x+2) = 0

2*x*(x+2)+1*(x+2)-9 = 0

2*x^2+4*x+x-9+2 = 0

2*x^2+5*x-7 = 0

2*x^2+5*x-7 = 0

2*x^2+5*x-7 = 0

DELTA = 5^2-(-7*2*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-5)/(2*2) or x = (-81^(1/2)-5)/(2*2)

x = 1 or x = -7/2

(x+7/2)*(x-1) = 0

((x+7/2)*(x-1))/(x+2) = 0

((x+7/2)*(x-1))/(x+2) = 0 // * x+2

(x+7/2)*(x-1) = 0

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -7/2, 1 }

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