2x+2(2x-2)=68

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Solution for 2x+2(2x-2)=68 equation: 



2x+2(2x-2)=68

We move all terms to the left:

2x+2(2x-2)-(68)=0

We multiply parentheses

2x+4x-4-68=0

We add all the numbers together, and all the variables

6x-72=0

We move all terms containing x to the left, all other terms to the right

6x=72

x=72/6

x=12

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