2x+2(2x-3)=3(x+5)

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Solution for 2x+2(2x-3)=3(x+5) equation: 



2x+2(2x-3)=3(x+5)

We move all terms to the left:

2x+2(2x-3)-(3(x+5))=0

We multiply parentheses

2x+4x-(3(x+5))-6=0



We calculate terms in parentheses: -(3(x+5)), so:

3(x+5)

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

6x-(3x+15)-6=0

We get rid of parentheses

6x-3x-15-6=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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