2x+2(4-2x)=9+5(x-3)

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Solution for 2x+2(4-2x)=9+5(x-3) equation: 



2x+2(4-2x)=9+5(x-3)

We move all terms to the left:

2x+2(4-2x)-(9+5(x-3))=0

We add all the numbers together, and all the variables

2x+2(-2x+4)-(9+5(x-3))=0

We multiply parentheses

2x-4x-(9+5(x-3))+8=0



We calculate terms in parentheses: -(9+5(x-3)), so:

9+5(x-3)

determiningTheFunctionDomain
5(x-3)+9

We multiply parentheses

5x-15+9

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We add all the numbers together, and all the variables

-2x-(5x-6)+8=0

We get rid of parentheses

-2x-5x+6+8=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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